]12V/:m] ]512 output RPM/:m] ]681 oz-in rated torque/:m]
My application:
]12V/:m] ]450-500 RPM/:m] ]141 oz-in rated torque/:m]
Clearly, this seems like a good fit. However, I saw the “warning” in the specs section of the linked gear motor above, claming, “[highlight=#ffffff][font=Helvetica Neue, Helvetica, Arial, sans-serif][size=4]Be careful though, as the maximum torque the gearbox can handle is lower than the stall torque of the motor, be sure to limit it’s output force.”[/size][/font][/highlight]
[highlight=#ffffff][font=Helvetica Neue, Helvetica, Arial, sans-serif][/font][/highlight]
This made me hesitate before purchasing- if I limit the output force, that’s doable- however, WHAT is that limit for the 9015 motor?
Although the continuous current at peak power or at peak efficiency are not provided, we can estimate that it would be around 1/3 to 1/4 stall.
“Stall” occurs when the motor does not have sufficient torque to rotate the shaft (something is physically impeding it). A motor is “dumb” so it will still try to rotate and as such, consume incredibly high current, causing it to heat up rapidly and destroy itself. As such, you should never operate a motor even close to its stall torque / stall current. The stall torque for that motor is 3.55 foot-pounds, so an estimate of the maximum continuous torque would be around 1 foot pound. They also indicated that it took 39 foot-pounds to physically break the metal shaft, though the motor would have long fried before it got anywhere close to that value.
