The duration of a note using
The duration of a note using the sound system is varied based on the processor speed. The default at 4 MHz is that a duration of 1 is about 10 ms. You’re code has a duration of 100, which would be a base of 1000 ms.
However, you are running a Picaxe-18m2, which runs at 32 MHz (8 times faster), so the duration will be approximately, 125 ms. I’m not sure how you are measuring the change in frequency every 100 ms, but this seems pretty close to that time period.
So I suspect that there is a slight delay every time your code loops. Either to check pinB.0 within the start0 loop or when you check pinB.0 in the main loop. Maybe for both. While this portion of the code executes, the sound is off. Howevever, it is off so briefly that you may interpret it as a change in the frequency of the note.
Try using a polled interrupt instead of checking the pins for their state, which is faster. This will happen in the background, and the code will get interrupted if the pin you are watching is changed. Interrupts are checked between every statement, between each note in a sound command, and continuously during pause commands.
So you could replicate your code using interrupts as shown below. Note that it is not necessary to use two pins for the interrupt. You use a single pin instead of both pin B.0 and B.1.
setint %00000010,%00000010,B 'activate interrupt on pin1 high on port B
main:
sound B.7,(0,100) 'Sound 0 is no sound
’Do whatever else you want to do in your program.
goto main
interrupt:
sound B.7,(100,100)
setint %00000010,%00000010 'you need to reset the interrupt each time
return
See how that works for you.
