I need to know how much torque will be required to move a .25 kg mass through 100mm straight up (more or less). Can someone point me toward a formula for figuring that out, so that I can determine what I need in the way of servo, stepper, or actuator? Torque rating is a good way to compare the relative power of servos, but I don’t know how to actually interpret the rating. Since the load is going straight up, the weight won’t change, so “kilos-per-millimeter” doesn’t seem to make sense. How do I make use of the torque information?
I think the question is different. I can convert kilos into pounds and mm into inches, but what does that resulting figure tell me about whether or not a given servo or actuator has enough poop to lift a half-pound (.25kg) weight straight up? The weight stays the same all the way up, so the distance shouldn’t matter. Torque is a measure of twisting force, but there’s no rotation or twisting going on here. Springs can be selected according to how much they can lift, but springs don’t have torque(unless they’re inside a grandfather clock). So how do I interpret the torque rating, either in/oz or N/mm, into a figure that will tell me whether or not the actuator can exert enough force to lift the weight? If I have to compute it based on length of lever arm or diameter of gear, fine-I’ll do that, but what is the formula? Should I call up Firgelli or Hitec? Thank you for considering the question.
First thing I noticed in the question was, there is no description of your mechanics involved. It’s hard to answer the question with half of the problem is missing. The following link might help. tutor4physics.com/index.php
In order to move a mass along a linear distance, it’s simply a question of force, not torque. Torque is used radially (like a car wheel). If you were using a pulley at the top of the 100mm, you would calculate torque = force x radius of pulley.