hi guys i new the forum but i wanted to know how to calculate torque required to lift the arm linkage at the pivot point on the attached drawing the mass of the arm is 10kg connected to the pivot point and the lenght of the arm is 1meter if you could help i would be greatful
hi what i am trying to workout is if the pivot point is driven by a motor how much torque would need to be applied by the motor
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ok thank you for your help
Hello.
I have a question about some of your products. I’m sorry I didnt create a new thread, but I didn’t know how.
I saw on the banebots.com website that robotshop is a distributor for their components, but I couldnt find the component I want to buy on this website. Is it possible to buy a product from you which is not listed here, only on the banebots website? If yes, how much time it will take it to arrive? I mention that I’m from Cluj-Napoca, Romania.
I’m reffering to this component: banebots.com/p/M7-RS775-18
Thank you
Torque(T) = force(F) x distance(d)
Notice how the distance ‘d’ is the perpendicular distance between the pivot and the point where the force is applied. If the force were to be applied at an angle, part of it would create a torque while part of it would act to compress the bar. The torque acts at the pivot point.
The torque needed by the motor is T, exactly as outlined. Once you calculate this, it’s important to have a safety factor; you might multiply this by 1.5 or 2x.
Torque is a rotational force and the units are force * distance (ex. N-cm). The motors puts out the torque. Some people convert this to weight * distance (Kg-cm, or oz-in).
Yes, we can special order it for you. Please contact us via the support center and provide your account, or your contact details, as well as the following code:
RB-Ban-00 M7-RS775-18
Hope this helps.
Wasn’t that the arrow in your original post? If it’s just the weight of the arm, then you can calculate the torque as 1/2 length of the arm (50cm) multiplied by its weight (10 Kg). Therefore the minimum torque required by the motor would be 500 kg-cm. We suggest at least a safety factor of 1.5, so the motor should be able to provide 750Kg-cm.
Once again, Torque should be a force (N for example) but most manufacturers have it as a mass.