If you have two servos that produce 25oz/in torque each, and you hook one up to pull the arms of the other, is there a formula that can predict the total torque of the system?
For instance here is an image I found of 2 in-line servos:
Thanks,
CF
Hi ChronoFish,First of all,
Hi ChronoFish,
First of all, I don’t think it’s 25 oz/in. Torque equals force times the perpendicular distance from the axis of rotation. So, I think that would be 25 oz x in i.e. 25 oz-in torque provided by each of the servos.
And about the total torque or net torque of the system, when both the servos move in a clockwise (CW) direction or in a counter-clockwise (CCW) direction ( in other words, if the individual torques are in the same direction), the torques would simply add up because the system is simply a horizontal plane. ( When both rotate CW, it might seem that the torques are opposite to each other but both are assisting the system. And same goes for them when they rotate CCW ).
If the servo’s torques oppose each other, ( one moving CW and the other CCW or vise versa ) the torques would simply cancel out each other to result zero torque ( and a few broken gears? I don’t know! )
At least this is what I think. But you might want to wait on for comments from some senior members ( bdk, Duane, DanM and the others ).
Thanks for the clarification
Obviously torque calculations are not my thing so I appreciate the clarification.
-CF