Hi,
I have four 4 wired load shields RB-Phi-118. And two Wheatstone shields RB–Onl-38. One Arduino Uno. In you article I will connect two load shields to (Strain1 and Strain2 connectors) of the first Wheatstone shield. Then place second Wheatstone shield on the top. I will bend A0 and A1 pins of the first Wheatstone shield and connect them to A2, A3 of the second Wheatstone shield. Then connect third and fourth load shields to (Strain1 and Strain2 connectors) of the second (topmost) Wheatstone shield. Is this right?
How does A0, A1 connection to A2, A3 help this?
regards
Sachin
Hi,
Yes, your understanding is correct.
Since the Load Cell / Wheatstone Amplifier Shield outputs the amplified load cell voltage on A0 (Strain 1) and A1 (Strain 2) analog pins, if you stack two of the shields, they will both output on A0 and A1 and you will have conflicting pins.
Bending A0 and A1 pin of the first shield and connecting it to A2 and A3 of the second shield will separate the outputs so that each load cell of the 4 load cells will output on its according pin :
]Load cell connected on Strain 1 of the first shield will output on A2./:m]
]Load cell connected on Strain 2 of the first shield will output on A3./:m]
]Load cell connected on Strain 1 of the second shield will output on A0./:m]
]Load cell connected on Strain 2 of the second shield will output on A1./:m]
